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0=-10x^2+130x-400
We move all terms to the left:
0-(-10x^2+130x-400)=0
We add all the numbers together, and all the variables
-(-10x^2+130x-400)=0
We get rid of parentheses
10x^2-130x+400=0
a = 10; b = -130; c = +400;
Δ = b2-4ac
Δ = -1302-4·10·400
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-30}{2*10}=\frac{100}{20} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+30}{2*10}=\frac{160}{20} =8 $
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